Hello, Future Chemist! Understanding Electron Transfer Reactions

Welcome to Electron Transfer Reactions! This chapter (Reactivity 3.2) is all about one of the most fundamental mechanisms of chemical change: the movement of electrons. Whether you're charging your phone, rusting a nail, or breathing, electron transfers are happening.

In this section, we will learn how to identify, track, and predict reactions where electrons are traded between species. Mastering these concepts is crucial because they connect thermodynamics (why reactions happen), kinetics (how fast they happen), and the real-world applications of electrochemistry (batteries and corrosion).


1. The Core Mechanism: Oxidation and Reduction (Redox)

An electron transfer reaction, often called a Redox reaction, is any chemical reaction in which the oxidation states of atoms are changed.

Don't worry if this seems tricky at first. It’s simply a "trade" where one species gives up electrons and another species accepts them. These two processes must occur simultaneously.

1.1 Defining Oxidation and Reduction

We define the two essential halves of the reaction using electron flow:

  • Oxidation: The loss of electrons.
  • Reduction: The gain of electrons.
The Essential Mnemonic: OIL RIG

This is your best friend in Redox chemistry:

Oxidation Is Loss (of electrons)
Reduction Is Gain (of electrons)

Example: If a Zinc atom (\(Zn\)) becomes a Zinc ion (\(Zn^{2+}\)), it loses two electrons. This is Oxidation: $$ Zn \rightarrow Zn^{2+} + 2e^- $$

Example: If a Copper ion (\(Cu^{2+}\)) gains two electrons to become a Copper atom (\(Cu\)), it is Reduction: $$ Cu^{2+} + 2e^- \rightarrow Cu $$

1.2 Oxidizing and Reducing Agents

In any chemical reaction, we must identify which chemical is causing the oxidation and which is causing the reduction.

  • Reducing Agent: The species that donates electrons, causing the other species to be reduced. (The reducing agent itself is oxidized.)
  • Oxidizing Agent: The species that accepts electrons, causing the other species to be oxidized. (The oxidizing agent itself is reduced.)


Quick Tip: The name of the agent is the name of the *process it causes* in the other chemical. If you are the reducing agent, you cause reduction.

Key Takeaway for Section 1
Redox reactions are coupled mechanisms. They involve the simultaneous loss and gain of electrons. The substance that is oxidized acts as the reducing agent, and the substance that is reduced acts as the oxidizing agent.

2. Tracking the Change: Oxidation States

Sometimes, electrons aren't completely lost or gained (like in covalent compounds), but the electron density shifts significantly. To track these changes consistently, chemists use Oxidation States (or Oxidation Numbers).

The oxidation state is a hypothetical charge an atom would have if all bonds were purely ionic. It is the core tool we use to confirm if a reaction is a Redox reaction.

2.1 Rules for Assigning Oxidation States

Memorize these basic rules (they are prioritized; rule 1 trumps rule 5):

  1. Free elements: The oxidation state of any uncombined element is zero (0). (e.g., \(Fe\), \(O_2\), \(H_2\))
  2. Monoatomic ions: The oxidation state equals the charge of the ion. (e.g., \(Cl^-\) is -1, \(Mg^{2+}\) is +2)
  3. Group 1 metals: Always +1 in compounds. (e.g., \(Na\), \(K\))
  4. Group 2 metals: Always +2 in compounds. (e.g., \(Mg\), \(Ca\))
  5. Fluorine (F): Always -1 in compounds.
  6. Hydrogen (H): Usually +1, except when bonded to a metal (metal hydride), where it is -1.
  7. Oxygen (O): Usually -2, except in peroxides (\(O_2^{2-}\)) where it is -1, or when bonded to Fluorine.
  8. Sum Rule: The sum of all oxidation states in a neutral compound must be zero. The sum in a polyatomic ion must equal the charge of the ion.

2.2 Identifying Redox from Oxidation State Changes

Once you assign the oxidation states to all atoms in a reaction, identifying oxidation and reduction is simple:

  • Oxidation: The oxidation state increases (becomes more positive/less negative).
  • Reduction: The oxidation state decreases (becomes less positive/more negative).

Example: Finding the oxidation state of Sulfur in \(SO_4^{2-}\)

The total charge is -2. Oxygen is usually -2.
\(S + 4(O) = -2\)
\(S + 4(-2) = -2\)
\(S - 8 = -2\)
\(S = +6\)
The oxidation state of Sulfur is +6.

Common Mistake Alert!
Oxidation States are written with the sign *before* the number (+6), while ionic charges are written with the sign *after* the number (\(6+\)). This distinction is important in IB examination style.

3. The Mechanism in Detail: Half-Equations and Balancing

To understand the mechanism of electron transfer, we separate the overall reaction into two half-equations: one for oxidation and one for reduction. This is essential for balancing complex redox reactions, especially those occurring in solution.

3.1 Balancing Half-Equations (The Step-by-Step Mechanism)

In IB Chemistry, you will usually balance reactions occurring in acidic solution (using \(H^+\) and \(H_2O\)).

Let's balance the reduction of permanganate ion (\(MnO_4^-\)) to manganese(II) ion (\(Mn^{2+}\)):

  1. Balance the Key Element: Balance the element being oxidized or reduced (Mn in this case). (It’s already balanced: 1 Mn on each side.)
  2. Balance Oxygen (O) Atoms: Add \(H_2O\) molecules to the side lacking oxygen. $$ MnO_4^- \rightarrow Mn^{2+} + 4H_2O $$
  3. Balance Hydrogen (H) Atoms: Add \(H^+\) ions to the side lacking hydrogen. $$ 8H^+ + MnO_4^- \rightarrow Mn^{2+} + 4H_2O $$
  4. Balance Charge (The Electron Transfer): Add electrons (\(e^-\)) to the side that is more positive to make the total charge equal on both sides.
    • Left side total charge: \((8 \times +1) + (-1) = +7\)
    • Right side total charge: \((+2) + (0) = +2\)
    • Difference = 5. Add \(5e^-\) to the left (more positive) side:
    $$ 5e^- + 8H^+ + MnO_4^- \rightarrow Mn^{2+} + 4H_2O $$

This final equation is the complete mechanism showing the reduction. The \(5e^-\) confirms the transfer of 5 electrons per \(MnO_4^-\) ion.

3.2 Combining Half-Equations

To get the overall, balanced net ionic equation, you must combine the oxidation and reduction half-equations such that the number of electrons lost equals the number of electrons gained.

  1. Balance the two half-equations separately (as above).
  2. Multiply one or both half-equations by integers so that the number of electrons in the oxidation half equals the number of electrons in the reduction half (the Lowest Common Multiple).
  3. Add the two equations together and cancel the electrons (and any spectator ions, \(H^+\), or \(H_2O\) molecules that appear on both sides).
Quick Review: Balancing Checklist
1. Key element (atoms)
2. O atoms (\(H_2O\))
3. H atoms (\(H^+\))
4. Charge (\(e^-\))

4. Practical Applications: Electrochemical Cells

Electron transfer reactions are not just theoretical; they are the mechanism behind devices that convert chemical energy into electrical energy, and vice versa. These devices are called electrochemical cells.

All electrochemical cells contain two key components:

  • Anode: The electrode where Oxidation occurs (An Ox).
  • Cathode: The electrode where Reduction occurs (Red Cat).


Did you know? The terms Anode and Cathode come from the Greek words for "path up" and "path down," reflecting the direction of electron flow in ancient electrical models.

4.1 Voltaic (Galvanic) Cells

A voltaic cell (or galvanic cell) harnesses the energy released by a spontaneous redox reaction to produce electrical energy. This is what we call a battery!

  • Energy Conversion: Chemical Energy \(\rightarrow\) Electrical Energy.
  • Spontaneity: The reaction is spontaneous (\(\Delta G < 0\)).
  • Electron Flow: Electrons flow externally from the anode (where they are lost) to the cathode (where they are gained).
  • Polarity: The Anode is the negative terminal; the Cathode is the positive terminal.
  • Salt Bridge: Essential component that allows ions to flow between the two half-cells to maintain electrical neutrality, preventing charge buildup that would stop the reaction.

Example: The classic Daniell Cell (Zn/Cu)
Oxidation (Anode): \(Zn(s) \rightarrow Zn^{2+}(aq) + 2e^-\)
Reduction (Cathode): \(Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)\)
Net Reaction: \(Zn(s) + Cu^{2+}(aq) \rightarrow Zn^{2+}(aq) + Cu(s)\)

4.2 Electrolytic Cells (Non-Spontaneous Reactions)

An electrolytic cell uses electrical energy to force a non-spontaneous redox reaction to occur.

  • Energy Conversion: Electrical Energy \(\rightarrow\) Chemical Energy.
  • Spontaneity: The reaction is non-spontaneous (\(\Delta G > 0\)); we must apply external voltage to "pump" the electrons.
  • Polarity: The Anode is connected to the positive terminal of the external power source; the Cathode is connected to the negative terminal. (Note: Oxidation still happens at the Anode, but the sign conventions relative to the external battery flip.)
  • Applications: Used in industrial processes like the extraction of reactive metals (e.g., Sodium or Aluminum), purifying metals, and electroplating (coating jewelry with a thin layer of gold).

Crucial Reminder: Regardless of the cell type, the chemical mechanism remains the same:

  • Anode = Oxidation (loss of electrons)
  • Cathode = Reduction (gain of electrons)

FINAL SUMMARY: The Mechanism of Electron Transfer

Electron transfer reactions (Redox) are characterized by a change in oxidation states, facilitating a mechanism where electrons are exchanged.

Mechanism Steps:
1. An electron is lost (Oxidation) by the Reducing Agent.
2. That electron is gained (Reduction) by the Oxidizing Agent.
3. This process can be made useful in Voltaic Cells (spontaneous, produce electricity) or forced in Electrolytic Cells (non-spontaneous, require electricity).